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64=0.0625x^2
We move all terms to the left:
64-(0.0625x^2)=0
We get rid of parentheses
-0.0625x^2+64=0
a = -0.0625; b = 0; c = +64;
Δ = b2-4ac
Δ = 02-4·(-0.0625)·64
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4}{2*-0.0625}=\frac{-4}{-0.125} =+32 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4}{2*-0.0625}=\frac{4}{-0.125} =-32 $
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